Line slope calculator x+4y=14
Straight line given by points A[2; 3] and B[6; 2]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+3.5
Canonical form of the line equation: x+4y-14 = 0
Parametric form of the line equation:
x = 4t+2
y = -t+3 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 14
Y intercept: y0 = q = 3.5
Distance line from the origin: d0 = 3.3955
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [4; 2.5]
Perpendicular Bisector equation: 4x-y-13.5 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 18
Angle ∠ AOB = 37°52'30″ = 0.661 rad