Line slope calculator 2x+5y=19


Enter coordinates of two different points:

Straight line given by points A[2; 3] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -0.4x+3.8

Canonical form of the line equation: 2x+5y-19 = 0

Parametric form of the line equation:
x = 5t+2
y = -2t+3      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 9.5

Y intercept: y0 = q = 3.8

Distance line from the origin: d0 = 3.5282

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [4.5; 2]

Perpendicular Bisector equation: 5x-2y-18.5 = 0


Vector OA = (2; 3) ;   |OA| = 3.6056
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 17
Angle ∠ AOB = 48°10'47″ = 0.8409 rad