Line slope calculator 2x+5y=19
Straight line given by points A[2; 3] and B[7; 1]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+3.8
Canonical form of the line equation: 2x+5y-19 = 0
Parametric form of the line equation:
x = 5t+2
y = -2t+3 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 9.5
Y intercept: y0 = q = 3.8
Distance line from the origin: d0 = 3.5282
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [4.5; 2]
Perpendicular Bisector equation: 5x-2y-18.5 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 17
Angle ∠ AOB = 48°10'47″ = 0.8409 rad