Line slope calculator 3x+7y=27
Straight line given by points A[2; 3] and B[9; 0]
Calculation:
Slope: m = -0.4286Slope-intercept form of line: y = -0.4286x+3.8571
Canonical form of the line equation: 3x+7y-27 = 0
Parametric form of the line equation:
x = 7t+2
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -23°11'55″ = -0.4049 rad
X intercept: x0 = 9
Y intercept: y0 = q = 3.8571
Distance line from the origin: d0 = 3.5453
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; -3)
Normal vector: n = (3; 7)
Midpoint of the segment AB: M = [5.5; 1.5]
Perpendicular Bisector equation: 7x-3y-34 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 18
Angle ∠ AOB = 56°18'36″ = 0.9828 rad