Line slope calculator 3x+8y=38
Straight line given by points A[2; 4] and B[10; 1]
Calculation:
Slope: m = -0.375Slope-intercept form of line: y = -0.375x+4.75
Canonical form of the line equation: 3x+8y-38 = 0
Parametric form of the line equation:
x = 8t+2
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -20°33'22″ = -0.3588 rad
X intercept: x0 = 12.6667
Y intercept: y0 = q = 4.75
Distance line from the origin: d0 = 4.4476
The length of the segment AB: |AB| = 8.544
Vector: AB = (8; -3)
Normal vector: n = (3; 8)
Midpoint of the segment AB: M = [6; 2.5]
Perpendicular Bisector equation: 8x-3y-40.5 = 0
Vector OA = (2; 4) ; |OA| = 4.4721
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 24
Angle ∠ AOB = 57°43'28″ = 1.0075 rad