Line slope calculator x-8y=-30
Straight line given by points A[2; 4] and B[10; 5]
Calculation:
Slope: m = 0.125Slope-intercept form of line: y = 0.125x+3.75
Canonical form of the line equation: x-8y+30 = 0
Parametric form of the line equation:
x = 8t+2
y = t+4 ; t ∈ R
Slope angle of line: φ = 7°7'30″ = 0.1244 rad
X intercept: x0 = -30
Y intercept: y0 = q = 3.75
Distance line from the origin: d0 = 3.721
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; 1)
Normal vector: n = (1; -8)
Midpoint of the segment AB: M = [6; 4.5]
Perpendicular Bisector equation: 8x+y-52.5 = 0
Vector OA = (2; 4) ; |OA| = 4.4721
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 40
Angle ∠ AOB = 36°52'12″ = 0.6435 rad