Line slope calculator 2x+3y=16


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -0.6667x+5.3333

Canonical form of the line equation: 2x+3y-16 = 0

Parametric form of the line equation:
x = 3t+2
y = -2t+4      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 8

Y intercept: y0 = q = 5.3333

Distance line from the origin: d0 = 4.4376

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [3.5; 3]

Perpendicular Bisector equation: 3x-2y-4.5 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 18
Angle ∠ AOB = 41°38'1″ = 0.7266 rad