Line slope calculator x+3y=14
Straight line given by points A[2; 4] and B[5; 3]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+4.6667
Canonical form of the line equation: x+3y-14 = 0
Parametric form of the line equation:
x = 3t+2
y = -t+4 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 14
Y intercept: y0 = q = 4.6667
Distance line from the origin: d0 = 4.4272
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [3.5; 3.5]
Perpendicular Bisector equation: 3x-y-7 = 0
Vector OA = (2; 4) ; |OA| = 4.4721
Vector OB = (5; 3) ; |OB| = 5.831
Scalar product OA .OB = 22
Angle ∠ AOB = 32°28'16″ = 0.5667 rad