Line slope calculator x+3y=14


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[5; 3]

Calculation:

Slope-intercept form of line: y = -0.3333x+4.6667

Canonical form of the line equation: x+3y-14 = 0

Parametric form of the line equation:
x = 3t+2
y = -t+4      ; t ∈ R

Slope: m = -0.3333

Slope angle of line: φ = -18°26'6″ = -0.3218 rad

X intercept: x0 = 14

Y intercept: y0 = q = 4.6667

Distance line from the origin: d0 = 4.4272

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; -1)

Normal vector: n = (1; 3)

Midpoint of the segment AB: M = [3.5; 3.5]

Perpendicular Bisector equation: 3x-y-7 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (5; 3) ;   |OB| = 5.831
Scalar product OA .OB = 22
Angle ∠ AOB = 32°28'16″ = 0.5667 rad