Line slope calculator x-3y=-10


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[5; 5]

Calculation:

Slope-intercept form of line: y = 0.3333x+3.3333

Canonical form of the line equation: x-3y+10 = 0

Parametric form of the line equation:
x = 3t+2
y = t+4      ; t ∈ R

Slope: m = 0.3333

Slope angle of line: φ = 18°26'6″ = 0.3218 rad

X intercept: x0 = -10

Y intercept: y0 = q = 3.3333

Distance line from the origin: d0 = 3.1623

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; 1)

Normal vector: n = (1; -3)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 3x+y-15 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 30
Angle ∠ AOB = 18°26'6″ = 0.3218 rad