Line slope calculator x+4y=18


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[6; 3]

Calculation:

Slope-intercept form of line: y = -0.25x+4.5

Canonical form of the line equation: x+4y-18 = 0

Parametric form of the line equation:
x = 4t+2
y = -t+4      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 18

Y intercept: y0 = q = 4.5

Distance line from the origin: d0 = 4.3656

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 4x-y-12.5 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 24
Angle ∠ AOB = 36°52'12″ = 0.6435 rad