Line slope calculator 4x+5y=28


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[7; 0]

Calculation:

Slope-intercept form of line: y = -0.8x+5.6

Canonical form of the line equation: 4x+5y-28 = 0

Parametric form of the line equation:
x = 5t+2
y = -4t+4      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 7

Y intercept: y0 = q = 5.6

Distance line from the origin: d0 = 4.3729

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [4.5; 2]

Perpendicular Bisector equation: 5x-4y-14.5 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (7; 0) ;   |OB| = 7
Scalar product OA .OB = 14
Angle ∠ AOB = 63°26'6″ = 1.1071 rad