Line slope calculator 3x+5y=26
Straight line given by points A[2; 4] and B[7; 1]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+5.2
Canonical form of the line equation: 3x+5y-26 = 0
Parametric form of the line equation:
x = 5t+2
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 8.6667
Y intercept: y0 = q = 5.2
Distance line from the origin: d0 = 4.459
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [4.5; 2.5]
Perpendicular Bisector equation: 5x-3y-15 = 0
Vector OA = (2; 4) ; |OA| = 4.4721
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 18
Angle ∠ AOB = 55°18'17″ = 0.9653 rad