Line slope calculator 3x+5y=26


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -0.6x+5.2

Canonical form of the line equation: 3x+5y-26 = 0

Parametric form of the line equation:
x = 5t+2
y = -3t+4      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 8.6667

Y intercept: y0 = q = 5.2

Distance line from the origin: d0 = 4.459

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [4.5; 2.5]

Perpendicular Bisector equation: 5x-3y-15 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 18
Angle ∠ AOB = 55°18'17″ = 0.9653 rad