Line slope calculator 2x-5y=-16


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[7; 6]

Calculation:

Slope-intercept form of line: y = 0.4x+3.2

Canonical form of the line equation: 2x-5y+16 = 0

Parametric form of the line equation:
x = 5t+2
y = 2t+4      ; t ∈ R

Slope: m = 0.4

Slope angle of line: φ = 21°48'5″ = 0.3805 rad

X intercept: x0 = -8

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 2.9711

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; 2)

Normal vector: n = (2; -5)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: 5x+2y-32.5 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (7; 6) ;   |OB| = 9.2195
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad