Line slope calculator 4x-5y=-12


Enter coordinates of two different points:

Straight line given by points A[2; 4] and B[7; 8]

Calculation:

Slope-intercept form of line: y = 0.8x+2.4

Canonical form of the line equation: 4x-5y+12 = 0

Parametric form of the line equation:
x = 5t+2
y = 4t+4      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = -3

Y intercept: y0 = q = 2.4

Distance line from the origin: d0 = 1.8741

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [4.5; 6]

Perpendicular Bisector equation: 5x+4y-46.5 = 0


Vector OA = (2; 4) ;   |OA| = 4.4721
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 46
Angle ∠ AOB = 14°37'15″ = 0.2552 rad