Line slope calculator 4x-5y=-12
Straight line given by points A[2; 4] and B[7; 8]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+2.4
Canonical form of the line equation: 4x-5y+12 = 0
Parametric form of the line equation:
x = 5t+2
y = 4t+4 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -3
Y intercept: y0 = q = 2.4
Distance line from the origin: d0 = 1.8741
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [4.5; 6]
Perpendicular Bisector equation: 5x+4y-46.5 = 0
Vector OA = (2; 4) ; |OA| = 4.4721
Vector OB = (7; 8) ; |OB| = 10.6301
Scalar product OA .OB = 46
Angle ∠ AOB = 14°37'15″ = 0.2552 rad