Line slope calculator 5x+8y=50
Straight line given by points A[2; 5] and B[10; 0]
Calculation:
Slope: m = -0.625Slope-intercept form of line: y = -0.625x+6.25
Canonical form of the line equation: 5x+8y-50 = 0
Parametric form of the line equation:
x = 8t+2
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -32°19″ = -0.5586 rad
X intercept: x0 = 10
Y intercept: y0 = q = 6.25
Distance line from the origin: d0 = 5.3
The length of the segment AB: |AB| = 9.434
Vector: AB = (8; -5)
Normal vector: n = (5; 8)
Midpoint of the segment AB: M = [6; 2.5]
Perpendicular Bisector equation: 8x-5y-35.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad