Line slope calculator 5x+8y=50


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.625x+6.25

Canonical form of the line equation: 5x+8y-50 = 0

Parametric form of the line equation:
x = 8t+2
y = -5t+5      ; t ∈ R

Slope: m = -0.625

Slope angle of line: φ = -32°19″ = -0.5586 rad

X intercept: x0 = 10

Y intercept: y0 = q = 6.25

Distance line from the origin: d0 = 5.3

The length of the segment AB: |AB| = 9.434

Vector: AB = (8; -5)

Normal vector: n = (5; 8)

Midpoint of the segment AB: M = [6; 2.5]

Perpendicular Bisector equation: 8x-5y-35.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad