Line slope calculator x+8y=42


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[10; 4]

Calculation:

Slope-intercept form of line: y = -0.125x+5.25

Canonical form of the line equation: x+8y-42 = 0

Parametric form of the line equation:
x = 8t+2
y = -t+5      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 42

Y intercept: y0 = q = 5.25

Distance line from the origin: d0 = 5.2095

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [6; 4.5]

Perpendicular Bisector equation: 8x-y-43.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (10; 4) ;   |OB| = 10.7703
Scalar product OA .OB = 40
Angle ∠ AOB = 46°23'50″ = 0.8098 rad