Line slope calculator x+8y=42
Straight line given by points A[2; 5] and B[10; 4]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+5.25
Canonical form of the line equation: x+8y-42 = 0
Parametric form of the line equation:
x = 8t+2
y = -t+5 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 42
Y intercept: y0 = q = 5.25
Distance line from the origin: d0 = 5.2095
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [6; 4.5]
Perpendicular Bisector equation: 8x-y-43.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 40
Angle ∠ AOB = 46°23'50″ = 0.8098 rad