Line slope calculator x-8y=-38


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[10; 6]

Calculation:

Slope-intercept form of line: y = 0.125x+4.75

Canonical form of the line equation: x-8y+38 = 0

Parametric form of the line equation:
x = 8t+2
y = t+5      ; t ∈ R

Slope: m = 0.125

Slope angle of line: φ = 7°7'30″ = 0.1244 rad

X intercept: x0 = -38

Y intercept: y0 = q = 4.75

Distance line from the origin: d0 = 4.7133

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; 1)

Normal vector: n = (1; -8)

Midpoint of the segment AB: M = [6; 5.5]

Perpendicular Bisector equation: 8x+y-53.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (10; 6) ;   |OB| = 11.6619
Scalar product OA .OB = 50
Angle ∠ AOB = 37°14'5″ = 0.6499 rad