Line slope calculator x-8y=-38
Straight line given by points A[2; 5] and B[10; 6]
Calculation:
Slope: m = 0.125Slope-intercept form of line: y = 0.125x+4.75
Canonical form of the line equation: x-8y+38 = 0
Parametric form of the line equation:
x = 8t+2
y = t+5 ; t ∈ R
Slope angle of line: φ = 7°7'30″ = 0.1244 rad
X intercept: x0 = -38
Y intercept: y0 = q = 4.75
Distance line from the origin: d0 = 4.7133
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; 1)
Normal vector: n = (1; -8)
Midpoint of the segment AB: M = [6; 5.5]
Perpendicular Bisector equation: 8x+y-53.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (10; 6) ; |OB| = 11.6619
Scalar product OA .OB = 50
Angle ∠ AOB = 37°14'5″ = 0.6499 rad