Line slope calculator 4x+y=13


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[3; 1]

Calculation:

Slope-intercept form of line: y = -4x+13

Canonical form of the line equation: 4x+y-13 = 0

Parametric form of the line equation:
x = t+2
y = -4t+5      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 3.25

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 3.153

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [2.5; 3]

Perpendicular Bisector equation: x-4y+9.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (3; 1) ;   |OB| = 3.1623
Scalar product OA .OB = 11
Angle ∠ AOB = 49°45'49″ = 0.8685 rad