Line slope calculator 4x+3y=23
Straight line given by points A[2; 5] and B[5; 1]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+7.6667
Canonical form of the line equation: 4x+3y-23 = 0
Parametric form of the line equation:
x = 3t+2
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 5.75
Y intercept: y0 = q = 7.6667
Distance line from the origin: d0 = 4.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [3.5; 3]
Perpendicular Bisector equation: 3x-4y+1.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 15
Angle ∠ AOB = 56°53'19″ = 0.9929 rad