Line slope calculator 5x-3y=-5
Straight line given by points A[2; 5] and B[5; 10]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x+1.6667
Canonical form of the line equation: 5x-3y+5 = 0
Parametric form of the line equation:
x = 3t+2
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = -1
Y intercept: y0 = q = 1.6667
Distance line from the origin: d0 = 0.8575
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [3.5; 7.5]
Perpendicular Bisector equation: 3x+5y-48 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (5; 10) ; |OB| = 11.1803
Scalar product OA .OB = 60
Angle ∠ AOB = 4°45'49″ = 0.0831 rad