Line slope calculator x-3y=-13


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[5; 6]

Calculation:

Slope-intercept form of line: y = 0.3333x+4.3333

Canonical form of the line equation: x-3y+13 = 0

Parametric form of the line equation:
x = 3t+2
y = t+5      ; t ∈ R

Slope: m = 0.3333

Slope angle of line: φ = 18°26'6″ = 0.3218 rad

X intercept: x0 = -13

Y intercept: y0 = q = 4.3333

Distance line from the origin: d0 = 4.111

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; 1)

Normal vector: n = (1; -3)

Midpoint of the segment AB: M = [3.5; 5.5]

Perpendicular Bisector equation: 3x+y-16 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (5; 6) ;   |OB| = 7.8102
Scalar product OA .OB = 40
Angle ∠ AOB = 18°15″ = 0.3142 rad