Line slope calculator 5x+4y=30


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -1.25x+7.5

Canonical form of the line equation: 5x+4y-30 = 0

Parametric form of the line equation:
x = 4t+2
y = -5t+5      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 6

Y intercept: y0 = q = 7.5

Distance line from the origin: d0 = 4.6852

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 4x-5y-3.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 12
Angle ∠ AOB = 68°11'55″ = 1.1903 rad