Line slope calculator 5x-4y=-10


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[6; 10]

Calculation:

Slope-intercept form of line: y = 1.25x+2.5

Canonical form of the line equation: 5x-4y+10 = 0

Parametric form of the line equation:
x = 4t+2
y = 5t+5      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = -2

Y intercept: y0 = q = 2.5

Distance line from the origin: d0 = 1.5617

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [4; 7.5]

Perpendicular Bisector equation: 4x+5y-53.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (6; 10) ;   |OB| = 11.6619
Scalar product OA .OB = 62
Angle ∠ AOB = 9°9'44″ = 0.1599 rad