Line slope calculator x+4y=22
Straight line given by points A[2; 5] and B[6; 4]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+5.5
Canonical form of the line equation: x+4y-22 = 0
Parametric form of the line equation:
x = 4t+2
y = -t+5 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 22
Y intercept: y0 = q = 5.5
Distance line from the origin: d0 = 5.3358
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [4; 4.5]
Perpendicular Bisector equation: 4x-y-11.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (6; 4) ; |OB| = 7.2111
Scalar product OA .OB = 32
Angle ∠ AOB = 34°30'31″ = 0.6023 rad