Line slope calculator x-4y=-18


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[6; 6]

Calculation:

Slope-intercept form of line: y = 0.25x+4.5

Canonical form of the line equation: x-4y+18 = 0

Parametric form of the line equation:
x = 4t+2
y = t+5      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -18

Y intercept: y0 = q = 4.5

Distance line from the origin: d0 = 4.3656

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; 1)

Normal vector: n = (1; -4)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 4x+y-21.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (6; 6) ;   |OB| = 8.4853
Scalar product OA .OB = 42
Angle ∠ AOB = 23°11'55″ = 0.4049 rad