Line slope calculator 3x+5y=31


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[7; 2]

Calculation:

Slope-intercept form of line: y = -0.6x+6.2

Canonical form of the line equation: 3x+5y-31 = 0

Parametric form of the line equation:
x = 5t+2
y = -3t+5      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 10.3333

Y intercept: y0 = q = 6.2

Distance line from the origin: d0 = 5.3165

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [4.5; 3.5]

Perpendicular Bisector equation: 5x-3y-12 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 24
Angle ∠ AOB = 52°15'11″ = 0.912 rad