Line slope calculator 2x+5y=29
Straight line given by points A[2; 5] and B[7; 3]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+5.8
Canonical form of the line equation: 2x+5y-29 = 0
Parametric form of the line equation:
x = 5t+2
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 14.5
Y intercept: y0 = q = 5.8
Distance line from the origin: d0 = 5.3852
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [4.5; 4]
Perpendicular Bisector equation: 5x-2y-14.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (7; 3) ; |OB| = 7.6158
Scalar product OA .OB = 29
Angle ∠ AOB = 45° = 0.7854 rad