Line slope calculator x+5y=27


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[7; 4]

Calculation:

Slope-intercept form of line: y = -0.2x+5.4

Canonical form of the line equation: x+5y-27 = 0

Parametric form of the line equation:
x = 5t+2
y = -t+5      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 27

Y intercept: y0 = q = 5.4

Distance line from the origin: d0 = 5.2951

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [4.5; 4.5]

Perpendicular Bisector equation: 5x-y-18 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (7; 4) ;   |OB| = 8.0623
Scalar product OA .OB = 34
Angle ∠ AOB = 38°27'13″ = 0.6711 rad