Line slope calculator x-5y=-23


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[7; 6]

Calculation:

Slope-intercept form of line: y = 0.2x+4.6

Canonical form of the line equation: x-5y+23 = 0

Parametric form of the line equation:
x = 5t+2
y = t+5      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -23

Y intercept: y0 = q = 4.6

Distance line from the origin: d0 = 4.5107

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [4.5; 5.5]

Perpendicular Bisector equation: 5x+y-28 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (7; 6) ;   |OB| = 9.2195
Scalar product OA .OB = 44
Angle ∠ AOB = 27°35'50″ = 0.4817 rad