Line slope calculator x-5y=-23
Straight line given by points A[2; 5] and B[7; 6]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+4.6
Canonical form of the line equation: x-5y+23 = 0
Parametric form of the line equation:
x = 5t+2
y = t+5 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -23
Y intercept: y0 = q = 4.6
Distance line from the origin: d0 = 4.5107
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [4.5; 5.5]
Perpendicular Bisector equation: 5x+y-28 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (7; 6) ; |OB| = 9.2195
Scalar product OA .OB = 44
Angle ∠ AOB = 27°35'50″ = 0.4817 rad