# Line slope calculator x-5y=-23

**Straight line given by points A[2; 5] and B[7; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+4.6

**Canonical form of the line equation:**x-5y+23 = 0

**Parametric form of the line equation:**

x = 5t+2

y = t+5 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -23

**Y intercept:**y

_{0}= q = 4.6

**Distance line from the origin:**d

_{0}= 4.5107

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[4.5; 5.5]

**Perpendicular Bisector equation:**5x+y-28 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (7; 6) ; |OB| = 9.2195**

**Scalar product OA .OB = 44**

**Angle ∠ AOB = 27°35'50″ = 0.4817 rad**