Line slope calculator 3x-5y=-19


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[7; 8]

Calculation:

Slope-intercept form of line: y = 0.6x+3.8

Canonical form of the line equation: 3x-5y+19 = 0

Parametric form of the line equation:
x = 5t+2
y = 3t+5      ; t ∈ R

Slope: m = 0.6

Slope angle of line: φ = 30°57'50″ = 0.5404 rad

X intercept: x0 = -6.3333

Y intercept: y0 = q = 3.8

Distance line from the origin: d0 = 3.2585

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; 3)

Normal vector: n = (3; -5)

Midpoint of the segment AB: M = [4.5; 6.5]

Perpendicular Bisector equation: 5x+3y-42 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 54
Angle ∠ AOB = 19°23'4″ = 0.3383 rad