Line slope calculator 5x+6y=40


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.8333x+6.6667

Canonical form of the line equation: 5x+6y-40 = 0

Parametric form of the line equation:
x = 6t+2
y = -5t+5      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 8

Y intercept: y0 = q = 6.6667

Distance line from the origin: d0 = 5.1215

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [5; 2.5]

Perpendicular Bisector equation: 6x-5y-17.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 16
Angle ∠ AOB = 68°11'55″ = 1.1903 rad