Line slope calculator x+6y=32


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[8; 4]

Calculation:

Slope-intercept form of line: y = -0.1667x+5.3333

Canonical form of the line equation: x+6y-32 = 0

Parametric form of the line equation:
x = 6t+2
y = -t+5      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 32

Y intercept: y0 = q = 5.3333

Distance line from the origin: d0 = 5.2608

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [5; 4.5]

Perpendicular Bisector equation: 6x-y-25.5 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (8; 4) ;   |OB| = 8.9443
Scalar product OA .OB = 36
Angle ∠ AOB = 41°38'1″ = 0.7266 rad