Line slope calculator 5x+7y=45
Straight line given by points A[2; 5] and B[9; 0]
Calculation:
Slope: m = -0.7143Slope-intercept form of line: y = -0.7143x+6.4286
Canonical form of the line equation: 5x+7y-45 = 0
Parametric form of the line equation:
x = 7t+2
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -35°32'16″ = -0.6202 rad
X intercept: x0 = 9
Y intercept: y0 = q = 6.4286
Distance line from the origin: d0 = 5.2311
The length of the segment AB: |AB| = 8.6023
Vector: AB = (7; -5)
Normal vector: n = (5; 7)
Midpoint of the segment AB: M = [5.5; 2.5]
Perpendicular Bisector equation: 7x-5y-26 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 18
Angle ∠ AOB = 68°11'55″ = 1.1903 rad