Line slope calculator 3x+7y=41
Straight line given by points A[2; 5] and B[9; 2]
Calculation:
Slope: m = -0.4286Slope-intercept form of line: y = -0.4286x+5.8571
Canonical form of the line equation: 3x+7y-41 = 0
Parametric form of the line equation:
x = 7t+2
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -23°11'55″ = -0.4049 rad
X intercept: x0 = 13.6667
Y intercept: y0 = q = 5.8571
Distance line from the origin: d0 = 5.3836
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; -3)
Normal vector: n = (3; 7)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: 7x-3y-28 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 28
Angle ∠ AOB = 55°40'11″ = 0.9716 rad