Line slope calculator 3x+7y=41


Enter coordinates of two different points:

Straight line given by points A[2; 5] and B[9; 2]

Calculation:

Slope-intercept form of line: y = -0.4286x+5.8571

Canonical form of the line equation: 3x+7y-41 = 0

Parametric form of the line equation:
x = 7t+2
y = -3t+5      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 13.6667

Y intercept: y0 = q = 5.8571

Distance line from the origin: d0 = 5.3836

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [5.5; 3.5]

Perpendicular Bisector equation: 7x-3y-28 = 0


Vector OA = (2; 5) ;   |OA| = 5.3852
Vector OB = (9; 2) ;   |OB| = 9.2195
Scalar product OA .OB = 28
Angle ∠ AOB = 55°40'11″ = 0.9716 rad