Line slope calculator 6x+y=18
Straight line given by points A[2; 6] and B[3; 0]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+18
Canonical form of the line equation: 6x+y-18 = 0
Parametric form of the line equation:
x = t+2
y = -6t+6 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 3
Y intercept: y0 = q = 18
Distance line from the origin: d0 = 2.9592
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [2.5; 3]
Perpendicular Bisector equation: x-6y+15.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (3; 0) ; |OB| = 3
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad