Line slope calculator 6x+y=18


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[3; 0]

Calculation:

Slope-intercept form of line: y = -6x+18

Canonical form of the line equation: 6x+y-18 = 0

Parametric form of the line equation:
x = t+2
y = -6t+6      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 3

Y intercept: y0 = q = 18

Distance line from the origin: d0 = 2.9592

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [2.5; 3]

Perpendicular Bisector equation: x-6y+15.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (3; 0) ;   |OB| = 3
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad