Line slope calculator 5x+y=16


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[3; 1]

Calculation:

Slope-intercept form of line: y = -5x+16

Canonical form of the line equation: 5x+y-16 = 0

Parametric form of the line equation:
x = t+2
y = -5t+6      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 3.2

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 3.1379

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [2.5; 3.5]

Perpendicular Bisector equation: x-5y+15 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (3; 1) ;   |OB| = 3.1623
Scalar product OA .OB = 12
Angle ∠ AOB = 53°7'48″ = 0.9273 rad