Line slope calculator 5x+2y=22
Straight line given by points A[2; 6] and B[4; 1]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+11
Canonical form of the line equation: 5x+2y-22 = 0
Parametric form of the line equation:
x = 2t+2
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 4.4
Y intercept: y0 = q = 11
Distance line from the origin: d0 = 4.0853
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 2x-5y+11.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 14
Angle ∠ AOB = 57°31'44″ = 1.0041 rad