Line slope calculator 3x+2y=18


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -1.5x+9

Canonical form of the line equation: 3x+2y-18 = 0

Parametric form of the line equation:
x = 2t+2
y = -3t+6      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 6

Y intercept: y0 = q = 9

Distance line from the origin: d0 = 4.9923

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [3; 4.5]

Perpendicular Bisector equation: 2x-3y+7.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 26
Angle ∠ AOB = 34°41'43″ = 0.6055 rad