Line slope calculator 3x+2y=18
Straight line given by points A[2; 6] and B[4; 3]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+9
Canonical form of the line equation: 3x+2y-18 = 0
Parametric form of the line equation:
x = 2t+2
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 6
Y intercept: y0 = q = 9
Distance line from the origin: d0 = 4.9923
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [3; 4.5]
Perpendicular Bisector equation: 2x-3y+7.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (4; 3) ; |OB| = 5
Scalar product OA .OB = 26
Angle ∠ AOB = 34°41'43″ = 0.6055 rad