Line slope calculator 5x+3y=28
Straight line given by points A[2; 6] and B[5; 1]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+9.3333
Canonical form of the line equation: 5x+3y-28 = 0
Parametric form of the line equation:
x = 3t+2
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 5.6
Y intercept: y0 = q = 9.3333
Distance line from the origin: d0 = 4.802
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [3.5; 3.5]
Perpendicular Bisector equation: 3x-5y+7 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 16
Angle ∠ AOB = 60°15'18″ = 1.0517 rad