Line slope calculator 5x+3y=28


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -1.6667x+9.3333

Canonical form of the line equation: 5x+3y-28 = 0

Parametric form of the line equation:
x = 3t+2
y = -5t+6      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 5.6

Y intercept: y0 = q = 9.3333

Distance line from the origin: d0 = 4.802

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [3.5; 3.5]

Perpendicular Bisector equation: 3x-5y+7 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 16
Angle ∠ AOB = 60°15'18″ = 1.0517 rad