Line slope calculator 4x-3y=-10


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[5; 10]

Calculation:

Slope-intercept form of line: y = 1.3333x+3.3333

Canonical form of the line equation: 4x-3y+10 = 0

Parametric form of the line equation:
x = 3t+2
y = 4t+6      ; t ∈ R

Slope: m = 1.3333

Slope angle of line: φ = 53°7'48″ = 0.9273 rad

X intercept: x0 = -2.5

Y intercept: y0 = q = 3.3333

Distance line from the origin: d0 = 2

The length of the segment AB: |AB| = 5

Vector: AB = (3; 4)

Normal vector: n = (4; -3)

Midpoint of the segment AB: M = [3.5; 8]

Perpendicular Bisector equation: 3x+4y-42.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (5; 10) ;   |OB| = 11.1803
Scalar product OA .OB = 70
Angle ∠ AOB = 8°7'48″ = 0.1419 rad