Line slope calculator 4x-3y=-10
Straight line given by points A[2; 6] and B[5; 10]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x+3.3333
Canonical form of the line equation: 4x-3y+10 = 0
Parametric form of the line equation:
x = 3t+2
y = 4t+6 ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = -2.5
Y intercept: y0 = q = 3.3333
Distance line from the origin: d0 = 2
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [3.5; 8]
Perpendicular Bisector equation: 3x+4y-42.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (5; 10) ; |OB| = 11.1803
Scalar product OA .OB = 70
Angle ∠ AOB = 8°7'48″ = 0.1419 rad