Line slope calculator x+4y=26


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -0.25x+6.5

Canonical form of the line equation: x+4y-26 = 0

Parametric form of the line equation:
x = 4t+2
y = -t+6      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 26

Y intercept: y0 = q = 6.5

Distance line from the origin: d0 = 6.3059

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 4x-y-10.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 42
Angle ∠ AOB = 31°45'34″ = 0.5543 rad