Line slope calculator 6x+5y=42
Straight line given by points A[2; 6] and B[7; 0]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+8.4
Canonical form of the line equation: 6x+5y-42 = 0
Parametric form of the line equation:
x = 5t+2
y = -6t+6 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 7
Y intercept: y0 = q = 8.4
Distance line from the origin: d0 = 5.3775
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [4.5; 3]
Perpendicular Bisector equation: 5x-6y-4.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (7; 0) ; |OB| = 7
Scalar product OA .OB = 14
Angle ∠ AOB = 71°33'54″ = 1.249 rad