Line slope calculator 4x+5y=38
Straight line given by points A[2; 6] and B[7; 2]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+7.6
Canonical form of the line equation: 4x+5y-38 = 0
Parametric form of the line equation:
x = 5t+2
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 9.5
Y intercept: y0 = q = 7.6
Distance line from the origin: d0 = 5.9346
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [4.5; 4]
Perpendicular Bisector equation: 5x-4y-6.5 = 0
Vector OA = (2; 6) ; |OA| = 6.3246
Vector OB = (7; 2) ; |OB| = 7.2801
Scalar product OA .OB = 26
Angle ∠ AOB = 55°37'11″ = 0.9707 rad