Line slope calculator 4x+5y=38


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[7; 2]

Calculation:

Slope-intercept form of line: y = -0.8x+7.6

Canonical form of the line equation: 4x+5y-38 = 0

Parametric form of the line equation:
x = 5t+2
y = -4t+6      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 9.5

Y intercept: y0 = q = 7.6

Distance line from the origin: d0 = 5.9346

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [4.5; 4]

Perpendicular Bisector equation: 5x-4y-6.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 26
Angle ∠ AOB = 55°37'11″ = 0.9707 rad