Line slope calculator 3x+5y=36


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[7; 3]

Calculation:

Slope-intercept form of line: y = -0.6x+7.2

Canonical form of the line equation: 3x+5y-36 = 0

Parametric form of the line equation:
x = 5t+2
y = -3t+6      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 12

Y intercept: y0 = q = 7.2

Distance line from the origin: d0 = 6.1739

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [4.5; 4.5]

Perpendicular Bisector equation: 5x-3y-9 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (7; 3) ;   |OB| = 7.6158
Scalar product OA .OB = 32
Angle ∠ AOB = 48°21'59″ = 0.8442 rad