Line slope calculator x+6y=38


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[8; 5]

Calculation:

Slope-intercept form of line: y = -0.1667x+6.3333

Canonical form of the line equation: x+6y-38 = 0

Parametric form of the line equation:
x = 6t+2
y = -t+6      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 38

Y intercept: y0 = q = 6.3333

Distance line from the origin: d0 = 6.2472

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [5; 5.5]

Perpendicular Bisector equation: 6x-y-24.5 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 46
Angle ∠ AOB = 39°33'35″ = 0.6904 rad