Line slope calculator 5x+7y=52


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -0.7143x+7.4286

Canonical form of the line equation: 5x+7y-52 = 0

Parametric form of the line equation:
x = 7t+2
y = -5t+6      ; t ∈ R

Slope: m = -0.7143

Slope angle of line: φ = -35°32'16″ = -0.6202 rad

X intercept: x0 = 10.4

Y intercept: y0 = q = 7.4286

Distance line from the origin: d0 = 6.0449

The length of the segment AB: |AB| = 8.6023

Vector: AB = (7; -5)

Normal vector: n = (5; 7)

Midpoint of the segment AB: M = [5.5; 3.5]

Perpendicular Bisector equation: 7x-5y-21 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 24
Angle ∠ AOB = 65°13'29″ = 1.1384 rad