Line slope calculator 3x+7y=48


Enter coordinates of two different points:

Straight line given by points A[2; 6] and B[9; 3]

Calculation:

Slope-intercept form of line: y = -0.4286x+6.8571

Canonical form of the line equation: 3x+7y-48 = 0

Parametric form of the line equation:
x = 7t+2
y = -3t+6      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 16

Y intercept: y0 = q = 6.8571

Distance line from the origin: d0 = 6.3027

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [5.5; 4.5]

Perpendicular Bisector equation: 7x-3y-25 = 0


Vector OA = (2; 6) ;   |OA| = 6.3246
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 36
Angle ∠ AOB = 53°7'48″ = 0.9273 rad