Line slope calculator 7x+8y=78
Straight line given by points A[2; 8] and B[10; 1]
Calculation:
Slope: m = -0.875Slope-intercept form of line: y = -0.875x+9.75
Canonical form of the line equation: 7x+8y-78 = 0
Parametric form of the line equation:
x = 8t+2
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -41°11'9″ = -0.7188 rad
X intercept: x0 = 11.1429
Y intercept: y0 = q = 9.75
Distance line from the origin: d0 = 7.3376
The length of the segment AB: |AB| = 10.6301
Vector: AB = (8; -7)
Normal vector: n = (7; 8)
Midpoint of the segment AB: M = [6; 4.5]
Perpendicular Bisector equation: 8x-7y-16.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 28
Angle ∠ AOB = 70°15'11″ = 1.2261 rad