Line slope calculator 2x+8y=68
Straight line given by points A[2; 8] and B[10; 6]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+8.5
Canonical form of the line equation: 2x+8y-68 = 0
Parametric form of the line equation:
x = 8t+2
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 34
Y intercept: y0 = q = 8.5
Distance line from the origin: d0 = 8.2462
The length of the segment AB: |AB| = 8.2462
Vector: AB = (8; -2)
Normal vector: n = (2; 8)
Midpoint of the segment AB: M = [6; 7]
Perpendicular Bisector equation: 8x-2y-34 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (10; 6) ; |OB| = 11.6619
Scalar product OA .OB = 68
Angle ∠ AOB = 45° = 0.7854 rad