Line slope calculator 6x+y=20
Straight line given by points A[2; 8] and B[3; 2]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+20
Canonical form of the line equation: 6x+y-20 = 0
Parametric form of the line equation:
x = t+2
y = -6t+8 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 3.3333
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 3.288
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [2.5; 5]
Perpendicular Bisector equation: x-6y+27.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (3; 2) ; |OB| = 3.6056
Scalar product OA .OB = 22
Angle ∠ AOB = 42°16'25″ = 0.7378 rad