Line slope calculator 5x+y=18


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[3; 3]

Calculation:

Slope-intercept form of line: y = -5x+18

Canonical form of the line equation: 5x+y-18 = 0

Parametric form of the line equation:
x = t+2
y = -5t+8      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 3.6

Y intercept: y0 = q = 18

Distance line from the origin: d0 = 3.5301

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [2.5; 5.5]

Perpendicular Bisector equation: x-5y+25 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (3; 3) ;   |OB| = 4.2426
Scalar product OA .OB = 30
Angle ∠ AOB = 30°57'50″ = 0.5404 rad