Line slope calculator 5x+y=18
Straight line given by points A[2; 8] and B[3; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+18
Canonical form of the line equation: 5x+y-18 = 0
Parametric form of the line equation:
x = t+2
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 3.6
Y intercept: y0 = q = 18
Distance line from the origin: d0 = 3.5301
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [2.5; 5.5]
Perpendicular Bisector equation: x-5y+25 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (3; 3) ; |OB| = 4.2426
Scalar product OA .OB = 30
Angle ∠ AOB = 30°57'50″ = 0.5404 rad